3x + 1 > 7 Solve ^ Help please it's for a test

In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsibl

schepotkina [342]

Answer:

$t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28$

The degrees of freedom are given by

$df=n-1=17-1=16$

The p value would be given by this probability:

$p_v =P(t_{(16)}$

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

$\bar X=8.19 cm^3$ represent the sample mean

$s=0.8 cm^3$ represent the sample deviation

$n=17$ sample size

$\mu_o =9.02$ represent the value to verify

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:

Null hypothesis: $\mu \geq 9.02$

Alternative hypothesis: $\mu < 9.02$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28$

The degrees of freedom are given by

$df=n-1=17-1=16$

The p value would be given by this probability:

$p_v =P(t_{(16)}$

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

6 0

3 years ago

A CD usually sells for $13.00. If the CD is 30% off, and sales tax is 5%, what is the total price of the CD, including tax?

Harlamova29_29 [7]

Answer:

$9.56

Step-by-step explanation:

$13.00 x .30 = 3.90

13.00 - 3.90 = $9.10 x .05 = 0.46

$9.10 + 0.46 = 9.56

7 0

3 years ago

If lia had 20 puppies, and then her friend took away 19 how many would be left

Slav-nsk [51]

There would be one puppy left.

8 0

3 years ago

Read 2 more answers

Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the favorite

Trava [24]

Answer:

The data are at the Nominal level of measurement.

The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.

Step-by-step explanation:

The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.

a)

The data are at the Nominal level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else

b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.

The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).

6 0

3 years ago

A travel agent currently has 80 people signed up for a tour. The price of a ticket is $5000 per person. The agency has chartered

Nikolay [14]

So hmm let's take a peek at the cost first

so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x

so, more than likely an insurance agency is charging them 300x for coverage

anyway, thus the cost C(x) = 250,000 + 300x

now, the Revenue R(x), is simple is jut price * quantity

well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits

so... let's see what the price say y(x) is $\bf \begin{array}{ccllll}
quantity(x)&price(y)\\
-----&-----\\
80&5000\\
81&4970\\
82&4940\\
83&4910
\end{array}\\\\
-----------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 80}}\quad ,&{{ 5000}})\quad 
% (c,d)
&({{ 83}}\quad ,&{{ 4910}})
\end{array}
\\\quad \\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-90}{3}\implies -30
\\ \quad \\\\
% point-slope intercept
y-{{ 5000}}={{ -30}}(x-{{ 80}})\implies y=-30x+2400+5000\\
\left.\qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=-30x+7400$

so.. now we know y(x) = -30x+7400

now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"

that simply means R(x) = -30x²+7400x

now, for the profit P(x)

the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)

P(x) = (7400x - 30x²) - (250,000+300x)

P(x) = -30x² + 7100x - 250,000

now, where does it get maximized? namely, where's the maximum for P(x)?

well $\bf \cfrac{dp}{dx}=-60x+7100$

and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum

7 0

3 years ago

3x + 1 > 7 Solve ^ Help please it's for a test ​

3x + 1 > 7 Solve ^ Help please it's for a test