Find the area of the shaded polygons:
1 answer:
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The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x , y = - (1/2)x .
A linear relationship in the form of y = mx + c is said to be a proportional relationship when c = 0 .
in the question
Part(a)
the equation is y (2)x - 3
on comparing it with y = mx + c , we get c = -3 , which is not 0 .
So , it is not a proportional relationship .
Part(b)
the equation is y (-2)x
on comparing it with y = mx + c , we get c = 0 ,
So , it is a proportional relationship .
Part(c)
the equation is y (3/5)x
on comparing it with y = mx + c , we get c = 0 ,
So , it is a proportional relationship .
Part(d)
the equation is y - (1/2)x
on comparing it with y = mx + c , we get c = 0 ,
So , it is a proportional relationship .
Therefore, The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x , y = - (1/2)x , that are options (b) , (c) and (d) .
The given question is incomplete , the complete question is
Which of the following linear relationships is NOT also a proportional relationship?
(a) y = (2)x - 3
(b) y = (-2)x
(c) y = (3/5)x
(d) y = - (1/2)x
Learn more about Proportionality here
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Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is
The standard deviation of the random sample is
Therefore, The mean is 2.5 and the standard deviation is 1.08.