You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
Answer:
hola a la par y me dijo dígame qué hora prefieres que te hace falta un poco pero no me e sentido así
Step-by-step explanation:
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Let the two numbers be x and y.
x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________
2x = 98
x = 98/2
x = 49
From x + y = 86
49 + y = 86
y = 86 - 49
y = 37
The numbers are 49 and 37.
Part A : 30 - x - x - x - x - x - x = 0
^ since 30 divided by 5 is 6, that answer is the same as doing 5 + 5 + 5 + 5 + 5 + 5
- pls comment & correct me if i did smth wrong :’)
I'm assuming you need to evaluate/simplify the equation, so you need to isolate/get x by itself in the equation:
2(3x + 1) = 11 Divide by 2 on both sides
3x + 1 =
[11/2 or 5.5] Subtract by 1 on both sides
[make the denominator the same to combine fractions]
3x =
Divide by 3 on both sides
x =