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2 years ago

Write the following in standard form: Write A = 4 B = 2 C = 7

Mathematics

1 answer:

bonufazy [111]2 years ago

7 0

Answer:

4x + 2y = 7

Step-by-step explanation:

The standard form equation goes as follows: Ax + By = C

We know what A, B, and C is so all we need to do is fill them in.

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

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Kay [80]

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Step-by-step explanation:

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Graph the line with slope <br> 2<br> 5<br><br> and <br> y<br><br> -intercept <br> −<br> 7<br><br> .

tia_tia [17]

Answer:

See attachment

Step-by-step explanation:

We want to graph the line with slope

$m = \frac{2}{5}$

and y-intercept ,

$b = - 7$

The equation of this line is

$y = \frac{2}{5}x - 7$

Starting at -7 on the y-axis, we run 5 units and rise 2 units right.

Then draw a line through the y intercept and the new point

The graph is shown in the attachment.

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3 years ago

the length of a rectangle is 3 more than the width. if the area is 40 square inches, what are the dimensions.

tankabanditka [31]

40 3 .......................

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3 years ago