Answer:
<em>B. The graph of g is the graph of f shifted 2 units down</em>
Step-by-step explanation:
<u>Graph of Functions</u>
We have two functions:
f(x)=3^x
g(x)=3^x-2
Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points
f(0)=3^0=1
g(0)=3^0-2=-1
f(1)=3^1=3
g(1)=3^1-2=1
f(3)=3^3=27
g(3)=3^3-2=25
We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is
B. The graph of g is the graph of f shifted 2 units down
Answer:
(-3,-1)
Step-by-step explanation:
When you graph it on a graphing paper, you can see that the graph touches it but barely
Answer:
uhhh wheres the question
Step-by-step explanation:
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian :
Akar-akar persamaan lama : x1 dan x2
Akar-akar persamaan baru : xA dan xB
xA = 2x1 - 1
xB = 2x2 - 1
xA + xB = (2x1 - 1) + (2x2 - 1)
= 2 (x1 + x2) - 2
= 2 () - 2
= 3 - 2
xA + xB = 1
xA . xB = (2x1 - 1) (2x2 - 1)
= 4 x1.x2 - 2(x1 + x2) + 1
= 4.(-) - 2() + 1
= -2 - 3 + 1
xA . xB = -4
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
x² - x - 4 = 0
</span></span>
B of course i think i hope
