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3 years ago

Locate and label each set of points on the coordinate plane. Describe similarities of the ordered pairs in each set,

Mathematics

2 answers:

Leya [2.2K]3 years ago

8 0

Answer:

THX FOR FREE POINT

Step-by-step explanation:

THANK YOU

Sergio039 [100]3 years ago

5 0

Answer:

The ordered pairs all have -coordinates of −, and the points lie along a vertical line above and below − on the -axis

Step-by-step explanation:

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Pls help me with this:(((((

marishachu [46]

2: c

Step-by-step explanation:

3: a

by Supplementing each answer Into the equation

6 0

2 years ago

Read 2 more answers

Which of the following equals 3x2−10x−83x2-10x-8 when factored completely?

xeze [42]

If it was typo and the original equation is 3x^2 - 10x - 8, then the answer would be (3x+2)(x-4), but if not then IDK.

Hope this helps!

4 0

3 years ago

Rational number between - 4/7 and 8/4

hjlf

Answer:

Hdujshshshddhdh

Step-by-step explanation:

4 0

2 years ago

What set of Reflections and rotations could carry ABCD onto itself?

Nitella [24]

Reflect over y-axis,reflect over the X axis ,rotate 180°

Option D is the correct option.

Explanation:

Let's take point A which is (4,-1)

Reflection over y- axis will make this point (4,1)

Then, reflection over X axis will make this point (4,-1)

After rotation of 180 degree we will get (-4,1) .

Please see the attached picture....

Hope it helps...

Good luck on your assignment...

6 0

3 years ago

Read 2 more answers

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$

$P(2>Z)=.97725$

We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

$P(-1$

Upon converting 0.81859 to percentage we will get

$0.81859*100=81.859\approx 81.86$

Therefore, 81.86% of final exam score will be between 68 and 86.

3 0

3 years ago