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3 years ago

I’m confused on this question

Mathematics

1 answer:

Flauer [41]3 years ago

5 0

There are ten left, I am going to use USD $ but it will be equal to euros. There are ten left, and 1/2 were sold for 5, 30 x 5 = 150. 1/3 were sold for 4, 20 x 4 = 80. 80 + 150 = 230. 60 x 3 = 180. 230-180=50. $2.5 each if she wants profit that adds up to $75.

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Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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7 0

1 year ago

At noon the temperature on Jessica's porch was 75 f .Then the temperature dropped d degrees. By midnight, the temperature on the

Nina [5.8K]

Answer:

D is 12

Step-by-step explanation:

75 - 63 = 12 = D

6 0

2 years ago

Help picture below problem 23 will give brainlest

Ksju [112]

Answer:

It will take them 5 hours to make 180 cupcakes

Step-by-step explanation:

17 + 19 = 36 x 5 = 180

5 0

2 years ago

Read 2 more answers

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

4 0

3 years ago

PLEASE HELP!! WILL REQARD A LOT

Soloha48 [4]

9514 1404 393

Answer:

17,500

Step-by-step explanation:

The problem can be written as a proportion:

hits/revenue = 1000/(£2) = x/(£35)

Multiplying by £35 gives ...

x = 1000(35/2) = 35000/2 = 17,500

17500 hits are required for revenue of £35.

3 0

3 years ago

Read 2 more answers