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wariber [46]
3 years ago
12

A prism is completely filled with 1120 cubes that have edge lengths of 1/2 in. What is the volume of the prism? Enter your answe

r in the box. in³
Mathematics
2 answers:
Ronch [10]3 years ago
6 0
Each cube has an edge length of 1/2 inch
V = 1/2 * 1/2 * 1/2
V = 1/8 cu in

There are 1120 of these cubes so the volume of the prism is 1/8 * 1120 = 140 cubic inches.

True [87]3 years ago
3 0
140 this is the answer

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Giving brainlist for correct answer. :))
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Answer:

Here is the steps. 67.5 cm^3

Step-by-step explanation:

4.5 * 6 = 27

27 * 2.5 = 67.5

4 0
2 years ago
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What is 75% as a fraction in simplest form
natulia [17]
75% = 75/100÷ 5= 15/20 ÷5= ¾.
3 0
3 years ago
The sum of two numbers is 30.the first number is 1/5 of the second number. what are the numbers?
gizmo_the_mogwai [7]
The 2md number can be y. This makes the first number 1/5 of y

Your equation is y + 1/5y = 30
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6 0
3 years ago
Larry read a 400400400-page book. He read at a rate of 101010 pages per day for ddd days. Write an equation that could be used t
ira [324]

Answer:

From Larry's rate, the equation can be given as D = T/101010

Step-by-step explanation:

Larry's book has 400400400 pages

His reading rate is 101010 pages per day

Let D = Number of days to read the book

To get the number of days it takes fro Larry to read this book, we say

Total pages = Reading rate (pages/day) x Number of days

Let Total pages = T

and Reading rate = R

Hence;

D = T / R

From Larry's rate, the equation can be given as D = T/101010.

From the question,

ddd = 400400400 (pages) / 101010 (pages/day) = 3963.9 days

Hence, it takes Larry approximately 3964 days to read the book.

7 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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