All categories

2 years ago

What is 2 5/6 ÷ 6 4/5

Mathematics

1 answer:

Anni [7]2 years ago

5 0

Answer:

17/42

Step-by-step explanation:

Just checked

You might be interested in

79-81 thank you so much!!

Novosadov [1.4K]

79.(b)this is because you have six choices, 3 red, 1 blue, 1 yellow, and 1 green and since it says not red you only have 3 choices, blue yellow and green, so the fraction would be 3/6. You can simplify the fraction by dividing it by 2 and you would get 1/2.

80.the answer will still be (b) which is the same explanation for 79.

81. (C) because remember that the first time you only had a 50% (1/2) chance of getting red and the second chance of getting a red will be the same but not
Its not likely You can get a red.

6 0

2 years ago

HELP (I WILL GIVE 30 POINTS)

pav-90 [236]

Answer:

4 ± 1/2sqrt(x) = y

This is not a function

Step-by-step explanation:

f(x) = (8-2x)^2

y = (8-2x)^2

To find the inverse function, exchange x and y and then solve for y

x = (8-2y)^2

Take the square root of each side

±sqrt(x) = 8-2y

Subtract 8 from each side

-8±sqrt(x) = 8-8-2y

-8±sqrt(x) = -2y

Divide by -2

-8/-2± 1/2sqrt(x) = -2/-2y

4 ± 1/2sqrt(x) = y

This is not a function

3 0

3 years ago

Read 2 more answers

The perimeter p of a regular hexagon varies directly with the length l of one side of the hexagon. What is an equation that rela

Oksi-84 [34.3K]

A hexagon has 6 sides, so the perimeter can be calculated as 6 x l. In other words:

$P = 6l$

I have attached what the graph to this will look like (looks like the graph y = 6x)

4 0

2 years ago

Calcule o valor de p na equação 6x^2 - 11x + (p - 1) = 0 para que o produto das raízes seja 2 terços

r-ruslan [8.4K]

Me no speak espanol. Hahahahaha. Can someone translate to English?

7 0

3 years ago

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.