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Talja [164]
3 years ago
8

I need answers plz here is the questions 80=-39+c

Mathematics
1 answer:
Maslowich3 years ago
6 0
The answer is c=119...:) hope it helps
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4. An amusement park developed a program for local fifth grade students to study the
Lesechka [4]

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A 1460

Step-by-step explanation:

Suppose that it is 185 students multiplied by 14 school districts.

ie 185*14=2590

4050-2590= 1460

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3 years ago
Need help fast!! Need steps also
ruslelena [56]

Answer:

arc AB = 3.14 in

Step-by-step explanation:

circumference of full circle = π2r = (3.14)(2)(6) = 37.68 in

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Which term best describes the graph of y = –2?
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It would be constant.

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2 years ago
What diagram do I use???
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5 0
3 years ago
Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s
r-ruslan [8.4K]

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
3 years ago
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