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sweet [91]
3 years ago
5

To find her total earnings for those two weeks Nadia writes 7.5 x 18.5 + 20 = 158.75 explain her error

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
7.5 x 18.5 = 138.75 
138.75 + 20 = 158.75
Her error is not writing down her pay per hour then multiplying it by her hours per day, then multiply that by 14 to get the 2 weeks pay.
Hope this helped!
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The graph shows the solution to which system of inequalities?
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Answer:

The orange one is the answer

Step-by-step explanation:

The easiest way to find the solution is to plug in one of the coordinates that is located in the shaded area into each equation. If the equations make sense, as they do in the orange option, you have your answer.

Hope this helps you!

7 0
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Plz help!!! Don’t understand
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Answer:it is no solution because the two lines don’t touch which means you can’t have points.

Step-by-step explanation:

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How to solve 2x-y=17;x-y=10
Nataliya [291]
The answer is that y is equal to -3 and x is equal to 7 
2x-y=17
-2(x-y)=10 )
--------------
2x-y=17
-2x+2y=-20
----------------
y=-3

x-y=10 
x-(-3)=10
x+3=10
 -3   -3
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x=7



8 0
3 years ago
Is every terminating decimal an integer?? Yes or no
sweet [91]
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7 0
3 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
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