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elena-s [515]
3 years ago
7

Which choice would reveal a chemical property of water?

Physics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

D

Explanation:

Testing The PH Means Testing The acidity level of the water of which would be a chemical reaction

You might be interested in
Find the magnitude & direction: 50N 25 N 35 N 10N
adoni [48]

F1x + F2x = Rx

↓

Rx = F1x + F2x

↓

Rx = F1 cos45° + F2

↓

Rx = (50N)(cos45°) + 60N

↓

Rx = 95N

Similarly, if we sum all the y components, we will get the y component of the resultant force:

F1y + F2y = Ry

↓

Ry = F1y + F2y

↓

Ry = F1 sin45° + 0

↓

Ry = F1 sin45°

↓

Ry = (50N)(sin45°)

↓

Ry = 35N

At this point, we know the x and y components of R, which we can use to find the magnitude and direction of R:

Rx = 95N

Ry = 35N

8 0
3 years ago
An 800-N billboard worker stands on a 4.0-m scaffold supported by vertical ropes at each end. If the scaffold weighs 500 N and t
Arturiano [62]

Answer:

T = 850 N

Explanation:

given,

mass of billboard worker = 800 N

length of scaffold = 4 m

weight of the scaffold = 500 N

worker is standing at 1 m from one end.

Tension in the rope = ?

To calculate the tension in the string we have to balance the clockwise and counterclockwise moment of the system.

Weight of the worker and the weight of the scaffold will be in clockwise direction where as the tension will be in counterclockwise direction

now,

800 x 3 + 500 x 2 = T x 4

4T = 3400

T = 850 N

hence, tension in the rope is equal to 850 N

5 0
4 years ago
In which of the following situations is the Doppler effect absent?
Bumek [7]
The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer
4 0
3 years ago
A star's life is a battle between what two forces?
Nana76 [90]
The outward push of the core created by nuclear fusion and the inward pull of gravity from the core
6 0
4 years ago
Read 2 more answers
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

7 0
3 years ago
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