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Ivanshal [37]
3 years ago
7

If an engine has a compression ratio of 7:1,

Physics
2 answers:
yanalaym [24]3 years ago
7 0

Answer:

A.

Explanation:

Compression ratio of an engine is defined as the ratio of the volume of gas in cylinder when the position is at TDC ( top dead center ) means top of its stroke to the volume of the gas when piston is at the bottom which is BDC or bottom dead center.

So if an engine has a compression ratio of 7 :  1 then it means the air and fuel mixture in the cylinder is squeezed into a space that is seven times smaller during the compression stage.

kolezko [41]3 years ago
6 0
The answer is A. Hope this helps!!!
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It has been a hot summer, so when you arrive at a lake, you decide to go for a swim even though it is nighttime. The water is co
ale4655 [162]

Answer: This is because water has a higher Specific Heat Capacity than air.

Explanation:

The specific heat capacity of an object measures how much heat will be required to change its temperature.

Water has a higher specific heat capacity than air, so the temperature of the water will remain fairly constant even though the air surrounding the water is experience temperature changes.

Since air has a lower Specific Heat Capacity than water, heat from the sun will readily heat it up in comparison to water.

6 0
4 years ago
In 1666 at the age of 23, what scientist
scoray [572]

Answer:

<h3>B - Isaac Newton</h3>

Explanation:

He first thought of his system of gravitation which he hit upon by observing an apple fall from a tree,

The incident occurring in the late summer of 1666.

3 0
3 years ago
A 75-hp (shaft output) motor that has an efficiency of 91% is worn out and is replaced by a high efficiency 75-hp motor that has
ZanzabumX [31]

Answer:

The heat gain of the room due to higher efficiency is 2.84 kW.

Explanation:

Given that,

Output power of shaft = 75 hp

Efficiency = 91%

High efficiency = 95.4%

We need to calculate the electric input given to motor

Using formula of efficiency

\eta=\dfrac{Work\ Output}{Work\ input}

Work\ Input =\dfrac{Work\ output}{\eta}

Work\ Input =\dfrac{75\times746}{0.91}

Work\ Input =61483.51\ W

Work\ Input = 61.48 kW

We need to calculate the electric input

For, heigh efficiency

Work\ Input_{inc} =\dfrac{75\times746}{0.954}

Work\ Input_{int} =58647.7\ W

Work\ Input_{int} = 58.64\ kW

The reduction of the heat gain of the room due to higher efficiency is

Q=Work\ Input-Work\ Input_{int}

Put the value into the formula

Q=61.48 -58.64

Q=2.84\ kW

Hence, The heat gain of the room due to higher efficiency is 2.84 kW.

3 0
3 years ago
C) m1:<br><br> D) m2: <br><br> E) r. <br><br> Please help me I need help now
Nesterboy [21]
A) F  = gravitational force

b) G = universal gravitational constant (6.67 × 10-11 N-m2/kg2)

c) m1 = mass of the body 1

d) m2 = mass of body 2

e) r = radius or distance between the two bodies.

Hope this helps!
6 0
3 years ago
Is electricity a compound, element, or a mixture?
sveta [45]
Electricity is a compound
3 0
4 years ago
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