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Ber [7]
3 years ago
5

19 books on a shelf. 8 of these books are new. The rest of them are used. What is the ratio of new books to used books

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

1:8

Step-by-step explanation:

You subtract 19 and 8, and you get 11 then you put them in ration form

Step-by-step explanation:

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Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
Find the product of (3x + 7y)(3x − 7y)
nalin [4]

Answer:

9x^2 - 49y^2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The shoes that Sofia wanted to buy at the mall were marked down from $30 to $24. What is the percentage of discount?
Nataliya [291]
30-24=6
6/30=1/5 aka 20%

The answer is 20%

Hope this helps.
8 0
3 years ago
Find the number of ways to distribute six different toys to three different children such that each child gets at least one toy.
Lisa [10]

Answer:

Step-by-step explanation:

Given that there are six different toys and they are to be distributed to three different children.

The restraint here is each child gets atleast one toy.

Let us consider the situation as this.

Since each child has to get atleast one toy no of ways to distribute

any 3 toys to the three children each.  This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways

So 3 toys to each one in 6x5x4 =120 ways

Now remaining 3 toys can be given to any child.

Hence remaining 3 toys can be distributed in 3x3x3 =27 ways

Total no of ways

= 120(27)

= 3240

8 0
3 years ago
Expand the following 5( 2x -4 )​
ycow [4]

Answer:

10x-20

Step-by-step explanation:

5(2x-4)

5x2=10

5x4=20

8 0
3 years ago
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