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Finger [1]
3 years ago
9

What equation passes through the point (-10,6) and is perpendicular to the line y=5x-4

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

y=-1/5x+4

Step-by-step explanation:

slope of y=5x-4 equals 5; a perpendicular line must be -1/5

6=-10(-1/5)+b

6=2+b

b=4

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Please help me <br><br>If 180°&lt;α&lt;270°, cos⁡ α=−8/17, what is sin -α?
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Starting from the fundamental trigonometric equation, we have

\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}

Since 180, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}

Plugging the numbers, we have

\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}

Now, just recall that

\sin(-\alpha)=-\sin(\alpha)

to deduce

\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}

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Find the range y=4-x domain =-2,3,5​
Wittaler [7]

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6 0
3 years ago
Can anyone pls pls pls help me in dis pls I will mark u as brainliest!!!!
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Answer:

See below.

Step-by-step explanation:

Infinite Solutions:

1. \:\:n=n\\\\2.\:\:y\cdot -6\cdot -3=2\cdot y\cdot 9\\\\3. \:\:5-9+3x=-10+6+3x\\\\4. \:\:2t+6=2(t+3)\\

No Solutions:

1. \:\:v+2=v-2\\\\2.\:\:\frac{1}{4}\left(20d+4\right)=5d\\\\3.\:\:3\left(n+1\right)=3n+1\\\\4.\:\:\frac{1}{2}+x=\frac{1}{3}+x

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