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Paraphin [41]
2 years ago
13

Y'all help me with the entire page please and thank you. also you better zoom in if you can't see

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
7 0

Answer:

i'm sorry but even after zooming in i still can't really read that.

what does it say?

Step-by-step explanation:

**i'll go back and answer, i promise**

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On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
erastovalidia [21]
Draw a picture of the problem.

let ∅ be the angle formed in the first quadrant such that its y coordinate is twice its x coordinate. 

The lengths are denoted 2a and a.

Joining the point (0, 0) to the point described, in the first quadrant, we have a right triangle with side lengths (2a, a,  \sqrt{5}a ), where \sqrt{5}a is the hypotenuse, found by the Pythagorean theorem.

sin∅=opposite side/hypotenuse= \frac{2a}{ \sqrt{5}a }= \frac{2}{\sqrt{5}}= \frac{2\sqrt{5}}{5}

Now consider the reflection of the red line segment with respect to the x-axis, the ratio of the distances described still holds. Since here we are in the fourth quadrant, the sine is negative, so sin is -\frac{2\sqrt{5}}{5}.



Answer: {{\frac{2\sqrt{5}}{5}, -\frac{2\sqrt{5}}{5}}}

6 0
3 years ago
Read 2 more answers
Is it possible to draw a triangle with all equal sides and unequal angles?
mart [117]
No, the triangle with all equal sides and equal angled is the equilateral triangle
7 0
2 years ago
NEED ANSWER ASAP PLEASE HELP ME OUT
-Dominant- [34]

Answer:

What exactly do you need help with?

Step-by-step explanation:

7 0
3 years ago
Mr. Burke had 40 pencil. He gave his class 1/5 of the pencils.Then he packed away 1/4 of the pencils that reminded. All the othe
Amiraneli [1.4K]

Answer:

26 pencils were thrown away.

Step-by-step explanation:

1/5 = 8/40

1/4 = 6/32

add them together 18/40

26 were thrown out

8 0
2 years ago
The legs of a right triangle have lengths of 4 and 5 units. what is the length of the hypotenuse
vlabodo [156]
This question can be solved using the Pythagorean theorem. a^2 + b^2 = c^2 where a and b are the legs of the triangle and c is the hypotenuse.

4^2 + 5^2 = c^2
16 + 25 = c^2
41 = c^2
\sqrt{41} = c
So, c is approximately 6.403.
3 0
2 years ago
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