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defon
3 years ago
15

Given a piece wise function f(x)={2x,x<1 5, x=1

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0
Pretty sure it’s 16TXI, hope this helps!
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-9=6+x zzzzZZZzzzzzzzzz
horrorfan [7]

Answer:

-15

Step-by-step explanation:

Isolate x to solve

-9=6+x

-6  -6

-15=x

4 0
3 years ago
Read 2 more answers
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
What is Derricka's goal, in miles, for the total distance she will swim on Monday, Tuesday, and Wednesday? Show your work.
denpristay [2]

Answer:

there is no backgroung information?

Step-by-step explanation:

3 0
3 years ago
PLS HELP I HAVE LEGIT 20 MINUTES TO FINISH BY 11:59 IM PANICKING PLS HELP WITH THESE QUESTIONS
poizon [28]
I’m pretty sure it is 19.2 units
5 0
2 years ago
Read 2 more answers
Which comparison statement is true? A. 7.24 &lt; 7.240 B. 7.24 &gt; 7.240 C. 7.24 = 7.240
KIM [24]
The answer is c they are equal to each other because the zero does not add anything to that number it is a place holder.


8 0
3 years ago
Read 2 more answers
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