Answer:

Step-by-step explanation:
Answer:
65 3 46
Step-by-step explanation:
*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5
Answer:
i think its the last option.
Step-by-step explanation:
its not the first one because they it can be proved using AAS (but that option isnt available)
You can't prove it with SSS or ASA without more info
AAA doesn't exist
theirfore it must be the last option.
Answer:
a. 20h + 8
Step-by-step explanation:
-2(-7h-4) + 6h = 14h + 8 + 6h = 20h + 8