Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
We can write the expanded form by writing each digit as a product of powers of 10.
Expanded form of 336,060 using exponents is given below:
![336060 = 3(10^{5} ) +3(10^{4} )+6(10^{3} )+6(10)](https://tex.z-dn.net/?f=336060%20%3D%203%2810%5E%7B5%7D%20%29%20%2B3%2810%5E%7B4%7D%20%29%2B6%2810%5E%7B3%7D%20%29%2B6%2810%29)
Y axis ofc A & B are the boxes
Answer:
B. 16p + 6
General Formulas and Concepts:
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(13p + 8) + (3p - 2)
<u>Step 2: Simplify</u>
- Combine like terms (p): 16p + 8 - 2
- Combine like terms (Z): 16p + 6