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neonofarm [45]
2 years ago
8

Write an equality that represents the graph below: (help me quick please)

Mathematics
2 answers:
insens350 [35]2 years ago
4 0

Answer:

A

Step-by-step explanation:

It's a solid dot that's going left, so it's less than or equal to. What integer is it on? -2. So it is either less than or equal to -2.

nasty-shy [4]2 years ago
4 0

Answer:

A

Step-by-step explanation:

since its closed its ≤ and going to the left means less than or equal to. :D

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A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Which of the following is an arithmetic sequence? -7/11 6/11 -5/11 4/11....
Anastasy [175]

Answer:

the right answer is \frac{3}{4} ,-\frac{3}{5},- \frac{3}{6} ,-\frac{3}{7}

Step-by-step explanation:

to find the reason for the sequence, the following formula must be used;

q = t2 / t1

where t2 is equal to the second value of the sequence and t1 to the first value.

q= t2/t1

q = \frac{-\frac{3}{5} }{-\frac{3}{4} } = \frac{12}{15} =\frac{4}{5}

8 0
3 years ago
Helppp plzzz idk I need help​
spin [16.1K]

Answer:

<em>T</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>y</em><em>.</em>

Step-by-step explanation:

<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>w</em><em>o</em><em>r</em><em>k</em><em>s</em><em> </em><em>o</em><em>u</em><em>t</em><em> </em><em>!</em><em>!</em>

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3 years ago
If the parent function is f(x) = x2 and its transformed function is g(x) = 2(x − 1)2 + 2, how is the graph of g(x) transformed f
Galina-37 [17]
The answer is A. g(x) is a vertical stretch and shift over both axes.
7 0
3 years ago
Read 2 more answers
I will give u brainliest
spayn [35]

Answer:

9

Step-by-step explanation:

sqrt(85) is about 9.2, and the question asks to round to the nearest integer, making it 9. 9.2^2 is almost 85, which is how you can check your answer.

4 0
3 years ago
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