Answer:
0.208mole of CO2
Explanation:
First, let us calculate the number of mole of HC3H3O2 present.
Molarity of HC3H3O2 = 0.833 mol/L
Volume = 25 mL = 25/100 = 0.25L
Mole =?
Mole = Molarity x Volume
Mole = 0.833 x 0.25
Mole of HC3H3O2 = 0.208mole
Now, we can easily find the number of mole of CO2 produce by doing the following:
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
From the equation,
1mole of HC2H3O2 produced 1 mole of CO2.
Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2
Feldspar<span>, A</span>ugite<span>, H</span>ornblende, and Zircon<span>.
Hope this helped!!!</span>
Answer:
<h2>4</h2>
Explanation:
1. Photorespiration occurs in plants and it is a wasteful pathway, it competes with the Calvin cycle. It begins when rubisco (Ribulose-1,5-bisphosphate carboxylase/oxygenase (RUBISCO) catalyzes both CO2 and O2 fixation) acts on O₂ instead of CO₂.
2. Photorespiration is initiated by the oxygenase activity of rubisco, the same enzyme that is also responsible for CO2 fixation.
3. Phosphoglycolate formed by O₂ fixation is recycled to the Calvin cycle intermediate phosphoglycerate in the photorespiratory pathway.
4. During oxygen fixation,1 molecule of PGA and 1 molecule of 2-phosphoglycolate are formed. The 2-phosphoglycolate is converted back to PGA in the photorespiratory cycle.
The answer to this is A i think.
Answer:
a CUT stands for Circuit Under Test.
Explanation: