The answer is a strike-slip. More specifically a right-lateral strike-slip.
Answer: 292.54g of Ag
Explanation:
Cu + 2AgNO3 →Cu(NO3)2 + 2 Ag
mass conc. Of Ag = n x molar Mass
Mass conc. Of Ag = 2 x 108 = 216g
From the equation,
63.5g of Cu produced 216g of Ag
Therefore, 86g of Cu will produce Xg of Ag. i.e
Xg of Ag = (86 x 216)/63.5 = 292.54g
Answer:
- last option: none of<u> the above.</u>
Explanation:
Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.
One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.
On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.
A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.
From above, there is no way that you can conclude whether a solution is supersaturated or not from the statement that a solution is concentrated, so the answer is<u> none of the above</u>.
Microgravity is your answer
Answer:
Explanation:
From the information given:
Step 1:
Determine the partial pressure of each gas at total Volume (V) = 4.0 L
So, using:
![Total pressure= P [N_2] + P[Ar] \ \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (0.525 + 1.7)Bar \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2.225 \ Bar](https://tex.z-dn.net/?f=Total%20pressure%3D%20P%20%5BN_2%5D%20%2B%20P%5BAr%5D%20%5C%20%5C%5C%20%5C%5C%20.%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%3D%20%280.525%20%2B%201.7%29Bar%20%5C%5C%20%5C%5C%20.%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%3D%202.225%20%5C%20Bar)
Now, to determine the final pressure using different temperature; to also achieve this, we need to determine the initial moles of each gas.
According to Ideal gas Law.
For moles N₂:
For moles of Ar:
Finally;
The final pressure of the mixture is:
P = 2.217 atm
P ≅ 2.24 bar
