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4 years ago

Find the moles of NaCl if 179.2L of CO2 at STP

Chemistry

1 answer:

777dan777 [17]4 years ago

5 0

16moles of NaCl

Explanation:

Given parameters:

Volume of NaCl = 19.21L

Unknown:

Number of moles of NaCl = ?

Solution:

To solve this problem, we should work from the known specie to the unknown one.

The known specie is the volume of CO₂ produce at STP;

Number of moles = $\frac{Volume at STP}{22.4L}$

Number of moles of CO₂ = $\frac{179.2}{22.4}$ = 8moles

From the balanced equation;

1 mole of CO₂ was produced along with 2 moles of NaCl

with 8 mole of CO₂ 8 x 2 mole of NaCl will be produced = 16moles of NaCl

learn more:

Gases at STP brainly.com/question/7795301

#learnwithBrainly

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Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.

lidiya [134]

First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

Concentration of [OH]⁻ in solution:

[ OH⁻ ] = $10 ^{-pOH}$

[ OH⁻ ] = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !

6 0

3 years ago

If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?

Pie

Answer:

$m = \frac{E}{c^2}$

$c = \sqrt{\frac{E}{m} }$

$E = 12.8 J$

Explanation:

Part 1: Solving for m

We are given that:

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

$m = \frac{E}{c^2}$

Part 2: Solving for c

We are given that:

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

$c^2 = \frac{E}{m}\\ \\ c=\sqrt{\frac{E}{m}}$

Part 3: Solving for E

We are given that:

m = 80 and c = 0.4

To get the value of E, we will simply substitute in the given equation:

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0

4 years ago

Calculate the enthalpy of the reaction

harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

$4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)$ $\Delta H_A=+2035kJ$

(2) $2B(s)+3H_2(g)\rightarrow B_2H_6(g)$ $\Delta H_B=+36kJ$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_C=-285kJ$

(4) $H_2O(l)\rightarrow H_2O(g)$ $\Delta H_D=+44kJ$

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

$\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D$

$\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)$

$\Delta H=-2552kJ$

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0

3 years ago

A second reaction mixture was made up in the following way:

Leya [2.2K]

A. We can calculate the initial concentrations of each by the formula:

initial concentration ci = initial volume * initial concentration / total mixture volume

where,

total mixture volume = 10 mL + 20 mL + 10 mL + 10 mL = 50 mL

ci (acetone) = 10 mL * 4.0 M / 50 mL = 0.8 M

ci (H+) = 20 mL * 1.0 M / 50 mL = 0.4 M (note: there is only 1 H+ per 1 HCl)

ci (I2) = 10 mL * 0.0050 M / 50 mL = 0.001 M

B. The rate of reaction is determined to be complete when all of I2 is consumed. This is signified by complete disappearance of I2 color in the solution. The rate therefore is:

rate of reaction = 0.001 M / 120 seconds

rate of reaction = 8.33 x 10^-6 M / s

6 0

4 years ago

Which of the following is not a physical property?

kozerog [31]

Answer: Reactivity is not a physical property, it is a chemical property.

Explanation:

Physical property is a value of matter that can be observed and measured without any change in composition of the matter. Examples of physical properties are color, combustion,melting point,boiling point,solubility, texture, appearance, polarity, odor,viscosity, density and many more.

Chemical properties are characteristics that are obvious or seen when substances undergo chemical reaction. Examples are reactivity,toxicity, acidity, flammability, and heat combustion.

5 0

3 years ago