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2 years ago

What system of inequalities is shown in the graph?

Mathematics

1 answer:

REY [17]2 years ago

3 0

I think the answer is C

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The answer to all of these word problem

user100 [1]

Answer:Hope this helps!

Number 1 = 2 and 1/8

Number 2 = 6 and 3/40

Number 5 = 4 and 2/6

Number 6 = 15 and 1/3

Step-by-step explanation:

3 0

3 years ago

The number of goals the Blue Jay hockey team scored in each game last year are: 3, 2, 1, 3, 0, 3, 1, 1, 2, 3, 3 What is the mode

oee [108]

Answer:

3 is the mode

Step-by-step explanation:

4 0

1 year ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago

On Sunday Sheldon bought 3 and 1/2kg of plant food. He used 1 and 2/3kg on his strawberry plants and used 1/4kg for his tomato p

notsponge [240]

The remaining plant food is: 1 7/12 kg

Step-by-step explanation:

Given

Total Plant food = 3 1/2 kg

Plant food used on Strawberry Plants = 1 2/3 kg

Plant food used on tomato Plants = 1/4 kg

We will first calculate the total food plant used and then subtract the used plant food from the total plant food.

So,

$Total\ Plant\ Food\ used=1\frac{2}{3}+\frac{1}{4}\\=\frac{5}{3}+\frac{1}{4}\\=\frac{20+3}{12}\\=\frac{23}{12}$

Now,

$Left\ Food\ Plant=3\frac{1}{2}-\frac{23}{12}\\=\frac{7}{2}-\frac{23}{12}\\=\frac{42-23}{12}\\=\frac{19}{12}\\=1\frac{7}{12}$

The remaining plant food is: 1 7/12 kg

Keywords: Division, Fractions

Learn more about fractions at:

#LearnwithBrainly

7 0

2 years ago

What dose the hypotenuse=?

Kitty [74]

Hypotenuse by Pythagoras theorem = 407.83.

3 0

3 years ago