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1 year ago

Which of the lines is a line of symmetry for the hexagon?

Mathematics

2 answers:

salantis [7]1 year ago

6 0

Answer:

The Correct Answer is B.JK and No.

Hope it helps you Czn.

Please Mark me as Brainleast!!!!!!

Crank1 year ago

5 0

Answer: the answer is b which is line NO and line JK

Step-by-step explanation: one line is vertical and the other is horizontal . Both lines make the sides equivalent and equal , so they make a symmetry . HOPE IT HELPS YOU BUDDY .PLEASE GIVE BRAINLIEST .THANKS ..

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Write the equation of the line, in slope-intercept form, with the following information: slope: -3/8 point: (16, -1)

irakobra [83]

Answer:

y+1=-3/8(x-16)

Step-by-step explanation:

I used the equation and plugged in the numbers

y-__y__=__m__(x-__x__)

6 0

2 years ago

Graph y=-1/2x^2-1. Identify the vertex of the graph. tell whether it is a minimum or maximum. (To clarify, 1/2 is a fraction *x^

ahrayia [7]

$y= -\frac{1}{2} x^{2}-1$ is a quadratic function, so its graph is a parabola.

Notice that the coefficient of x is 0, this always means that the axis of symmetry is the y-axis.

That is, the vertex of the parabola is in the y-axis, so the x-coordinate of the vertex is 0.

for x=0, y=-1. So the vertex is (0, -1)

The coefficient of $x^{2}$ is negative. This means that the parabola opens downwards, so the vertex is a maximum.

Answer: (0, -1) , maximum (none of the choices)

5 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

Given the line y=3/5x+2 find the perpendicular line passing through the point (12,-7)

Monica [59]

Answer:

y=-5/3x+13.

Step-by-step explanation:

As a line that is perpendicular to anoher line has a slope that is the negative reciprocal of the line's original slope, we know that the slope of our new line is -5/3. As it passes point (12, -7), we can use the point slope formula which is y-y1=m(x-x1). So plug in, y+7=-5/3(x-12) and that gives us y+7=-5/3x+20 which gives our final answer of y=-5/3x+13.

7 0

2 years ago

The area of a rectangle is 99 ft^2, and the length of the rectangle is 7 more than double the width. Find the dimensions of the

Sergio039 [100]

Answer:

width =5.5ft

length =18

Step-by-step explanation:

w=x

L=2x+7

area=w*L

99 = x(2x+7)

$99=2x^{2} +7x$

$2x^{2} +7x-99=0$

$2x^{2} +18x-11x-99=0$

2x(x+9)-11(x+9)=0

(2x-11)(x+9)=0

2x-11=0

2x=11

x=11/2

x=5.5

L=2x+7=2*5.5+7=11+7=18

7 0

3 years ago