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dalvyx [7]
3 years ago
14

For each of the regions D in R^2 below, fill in the blank so that the statements are true:

Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

b. might or might not

Step-by-step explanation:

For each of the regions D in R^2 below, fill in the blank so that the statements are true: <u>might or might not</u>

andrey2020 [161]3 years ago
7 0

Answer:

b. might or might not

Step-by-step explanation:

Theorem:

If f is a continuous function in a bounded interval, it must have an absolute maximum.

In this question:

The interval is  2x^4+6y^2 >= 152, which goes to infinite, meaning it is not bounded, and so the function might or might not have an absolute maximum, and the correct answer is given by option b.

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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

P=\int^{T}_{0}f(t)e^{-rt}dt

where:

  • T is the period in years (T = 10 years)
  • r is the annual interest rate (r=0.08)

So we have:

P=\int^{T}_{0}(0.01t+100)e^{-rt}dt

Now we just need to solve this integral.

P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt

P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}

P=0.30+688.34=688.64 $

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P

A=e^{0.08\cdot 10}688.64=1532.60 $

The accumulated amount is 1532.60 $

Have a nice day!

6 0
3 years ago
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