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ss7ja [257]
3 years ago
7

Please help me can y’all tell me how to solve it out

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

40in

Step-by-step:

to get from 12 to 30 you multiply by 2.5

this is the scale factor

then you do 16 x 2.5 which is 40

pq (p to q) is 40in

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HELP NEEDED PLEASE!!!
postnew [5]

Using vector concepts, it is found that:

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

<h3>How can a vector be represented in component notation?</h3>

Given a magnitude M and angle \theta, then a vector V can be represented as follows in component notation:

V = (M\cos{\theta}, M\sin{\theta})

In this problem, the magnitude and the angle are given, respectively, by:

M = 12, \theta = 143^\circ

Hence:

V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).

Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

More can be learned about vectors at brainly.com/question/24606590

#SPJ1

8 0
2 years ago
In AUVW, v = 39 inches, u = 37 inches and ZU=66º. Find all possible values
Debora [2.8K]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
In ΔRST, m &lt; R = 104°, r = 20, and t = 10. Find the m &lt; S, to nearest degree.
Mrrafil [7]

9514 1404 393

Answer:

  47°

Step-by-step explanation:

The law of sines helps you find angle T. From there, you can find angle S.

  sin(T)/t = sin(R)/r

  sin(T) = (t/r)sin(R) = (10/20)sin(104°)

  T = arcsin(sin(104°)/2) ≈ 29°

Then angle S is ...

  S = 180° -R -T = 180° -104° -29°

  ∠S = 47°

5 0
3 years ago
To describe a sequence of transformations that maps triangle ABC onto triangle a"b"c", a student starts with a reflection over t
Paha777 [63]

i dont quite get the question but...

i guess this is how it is.

Take the mirror image of∆ABC Through the a line through the point y=3.

The new ∆ABC would have point C=(4,2)

B=(3,-6) A=(1,-3)

Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>

We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).

This coordinate is the same coordinates of ∆A"B"C".

Hope it helps...

Regards;

Leukonov/Olegion.

8 0
3 years ago
Appreciate the support!
andreyandreev [35.5K]

The volume of a rectangular prism is represented by the following equation:

V=w*h*l

Where the variables are for volume, width, height, and length, respectively.

We are given that the area of one end is 16 cm² (units have to be correct when solving these problems, so it's 16 cm², not 16 cm as described in the problem). We know that A=w*h

Using this knowledge, we can change the volume equation to our needs.

V=w*h*l

V=(w*h)*l

V=A*l

Note: We know that A is 16 since it's given

V=16*l

The volume is 208 cm³ (once again, incorrect units given). Insert this into the equation.

208=16*l

Divide both sides of the equation by 16.

13=l

The length is 13 cm.

Let me know if you need any clarifications, thanks!

4 0
3 years ago
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