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liberstina [14]
3 years ago
13

A bet in roulette has a probability of 18/38 of winning. If you win, you double your money. You can bet anywhere from $1 to $100

on each spin. A. Suppose you have $10, and are going to play until you go broke or have $20. What is your best strategy for playing? Explain using information you learned in this module's material, such as expected value. B. Suppose you have $10, and are going to play until you go broke or have $30. What is your best strategy for playing?
Mathematics
1 answer:
dalvyx [7]3 years ago
6 0

b. Suppose you have $10, and are going to play until you go broke or have $30. What is your best strategy for playing? Explain using information you learned in this module's material, such as expected value

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262000000 scientific notation
viktelen [127]

Answer:

2.62 × 10^8

would be the scientific notation equation that when solved gives you 262000000

8 0
3 years ago
The acceleration function a(t) (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.
klemol [59]

Answer:

A: v(t)=-t^2+4t-5

Step-by-step explanation:

Acceleration is second derivative of position, velocity is first derivative. Therefore, the velocity is the integral of acceleration.

v(t)=\int\ {2t+4} \, dt

Integrate:

-t^2+4t+C

V(0)=-5:

-0^2+4(0)+C=-5\\C=-5

Therefore, v(t):

v(t)=-t^2+4t-5

7 0
3 years ago
Please help! Will give Brainliest!
Serhud [2]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
a baseball bat used in sale for $30.00.It has been discounted at half off.What was th original pruce of the bat?
Umnica [9.8K]

Answer:

15$

Step-by-step explanation:


3 0
3 years ago
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