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Alisiya [41]
3 years ago
15

Which is the graph of an even monomial function?

Mathematics
1 answer:
Cloud [144]3 years ago
4 0

Answer:

The graph of an even function is symmetric about the y-axis. The graph of an odd function is symmetric about the x-axis. It is possible that the use of these two words originated with the observation that the graph of a polynomial function in which all variables are to an even power is symmetric about the y -axis.

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What is the quotient of the division below? 96-3= O 13 O 23 O 31 o 32​
Anastaziya [24]

Answer:

the answer is 32

Step-by-step explanation:

hope this help have a good day

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3 years ago
What is 3.2 as a fraction
Anastasy [175]
3.2
=3+2/10
=3+1/5
=16/5
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3 years ago
Factor the expression using the GCF. The expression 21m−49n factored using the GCF is...
Roman55 [17]

Answer:  7(3m - 7n)

<u>Step-by-step explanation:</u>

Factor each term then see what value(s) they have in common:

          21m         -          49n

            ∧                        ∧

          3 · 7 · m              7 · 7 · n

Both terms have a 7 in common.  What is left over after removing the 7?

21m: 7(3m)

49n: 7(7n)

GCF: 7           Leftovers: 3m <em>and</em>  7n

Factored form of expression is: 7(3m - 7n)

6 0
3 years ago
Read 2 more answers
Solve for y ax+by=c help asap
jekas [21]
ax + by = c\\\\by = c - ax\\\\\boxed{y = \frac{c-ax}{b}}
7 0
3 years ago
In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
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