Which of the following integers is least?
2 answers:
Answer:
Option A is correct.
Step-by-step explanation:
Option A).
Given: -5 + ( -2 )
-5 + ( -2 ) = -5 - 2 = -7
Option B).
Given: -5 ÷ ( -2 )
Option C).
Given: -5 × ( -2 )
-5 × ( -2 ) = 10
Option D).
Given: -5
So we have -7 , 2.5 , 10 , -5
Among these -7 is the integer which has least value as it comes of left side of all other numbers on number line.
Therefore, option A is correct.
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There are 12 possible arrangements.
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- Considering that the blue cup has to be on one end, we consider the number of arrangements possible with the other 4 cups, then multiply by 2(considering the blue on each end).
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- Considering green and yellow before red and purple, there are
outcomes(G-Y-R-P, G-Y-P-R, Y-G-R-P and Y-G-P-R).
- Another two possible outcomes are yellow-purple and green-red, or vice-versa, thus 4 + 2 = 6 outcomes.
- To account for the blue on the end, multiplying by 2.
- There are 12 possible arrangements.
A similar problem is given at brainly.com/question/24617788
1. Use the FOIL method (x+9)(x+9)
First, outer, inner, last
Add your like terms
2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.
3.
4. Since it is the perimeter, we add the 3 together.
Add the like terms together:
Put them in order of exponents
Hope this helps
First, outer, inner, last
Add your like terms
2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.
3.
4. Since it is the perimeter, we add the 3 together.
Add the like terms together:
Put them in order of exponents
Hope this helps