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VARVARA [1.3K]
3 years ago
14

The Pythagorean Theorem applies to any type of triangle.

Mathematics
2 answers:
taurus [48]3 years ago
8 0
False it needs to be a right triangle with a hypotenuse
Alexxandr [17]3 years ago
3 0
False. it has to be a right triangle
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PLEASE HELP I AM BEGGING YOU!!! I WILL GIVE BRAINLIEST AND EXTRA POINTS PLEASEEEEEEEEEEEEEEEEEE!!!!!!!
san4es73 [151]

Answer:

1. 31

2. -40

3. 28.5

4. 75

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6. -24

7. -34

8. 68

9. 8

10. 26

Step-by-step explanation:

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4 0
3 years ago
Please help me find the value of x the answer must be exact
jenyasd209 [6]

Answer:

x=11

Step-by-step explanation:

This is a 45°-45°-90° triangle. The two legs are the same length, and the hypotenuse is that length times the square root of two:

leg=x\\hypotenuse=x\sqrt{2}

Therefore, the value of x is 11.

You can double-check using the sine ratio:

sineX=\frac{opposite}{hypotenuse}

Insert the values:

sin45=\frac{x}{11\sqrt{2} }

Insert the equation into a calculator:

x=11

:Done

*It's important to know that, when working with trigonometry ratios, the hypotenuse is never considered the adjacent or opposite side, and the 90° angle is never used in the ratios.

6 0
3 years ago
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kolezko [41]
A < -12

1/3a < -4
a < -12


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5 0
3 years ago
Read 2 more answers
Can you guys please help. I really don't know how to solve this
Nonamiya [84]

The inequalities that can be used to represent this problem are x < 0 or x > 5. On the number line, you will want to place an open circle on both 0 and 5. The open circle signifies that x is not equal to these values, but is greater or less than. On the open circle on 0, draw an arrow pointing left, toward the negative values. On the open circle on 5, draw an arrow pointing right, toward the positive values.

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3 0
3 years ago
Solve the proportion.<br><br> s+1/4 = 4/8<br> s=
LUCKY_DIMON [66]

Answer:

8 = 16

Step-by-step explanation:

1/4  =  4 /8

 

Cross multiply:

1 * 8 = 4 * 4

Simplifying

1 * 8 = 4 * 4

Multiply 1 * 8

8 = 4 * 4

Multiply 4 * 4

8 = 16

Solving

8 = 16

3 0
3 years ago
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