Assuming you want the slope, the answer is -2/-3.
X-change: -2
Y-change: -3
X-c/Y-c = -2/-3
If -2/-3 is not an answer, try 2/3 or .666 (infinite 6s).
Answer:
52.38%
Step-by-step explanation:
P(991<X<997) = normalcdf(991,997,993,4) = 0.5328, therefore, about 52.38% of the bottles have volumes between 991 mL and 997 mL
Answer:
Volume of prism = 39 km cubed
Step-by-step explanation:
<u>IMPORTANT FORMULA: Volume of any prism = Area of base * Height </u>
<u />
In this case, <u><em>the area of the base</em></u> means <u><em>the area of the trapezoid. </em></u>
Area of trapezoid = base1+base2/2 * height
Area of trapezoid = 8+5/2 * 1.5
Area of trapezoid = 13/2 * 1.5 = 9.75
We already know that the height of the trapezoidal prism is 4 kilometers.
So, we have all of the values that are needed to correctly fill in the formula.
Volume of the prism = 9.75 * 4 = 39
Answer: Adenike scored 64 marks, while Musa scored 45 marks
Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.
First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as
3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;
d = 19 + m ———(1)
3d/2 = 6 + 2m ———(2)
Substitute for the value of d into equation (2), if d = 19 + m
(3{19 + m})/2 = 6 + 2m
By cross multiplication we now have
3(19 + m) = 2(6 + 2m)
57 + 3m = 12 + 4m
We collect like terms and we have
57 - 12 = 4m - 3m
45 = m
We now substitute for the value of m into equation (1)
d = 19 + m
d = 19 + 45
d = 64
So Adenike scored 64 marks while Musa scored 45 marks
Answer:
z' = 2iz +11 -2i
Step-by-step explanation:
Dilation multiplies each point by the scale factor. Rotation by 90° CCW is equivalent to multiplication by i.
When the center is not the origin, the transformation is applied to the difference from the center, then the result is added to the center.
z' = 2i(z -(3+4i)) + (3+4i)
Simplifying gives ...
z' = 2iz -6i +8 +3 +4i
z' = 2iz +11 -2i
_____
<em>Check</em>
For example, consider the point 1 unit east of the center of dilation/rotation. That point is z = 4+4i. Applying the transformation moves this point to ...
z' = 2i(4 +4i) +11 -2i = 8i -8 +11 -2i
z' = 3 +6i . . . . . 2 units north of the center of dilation/rotation
This is where it is expected to be after dilation by a scale factor of 2 and rotation 90° CCW.