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Illusion [34]
2 years ago
15

Given the QY’=4.125, what is QY?

Mathematics
1 answer:
Goryan [66]2 years ago
3 0

Answer:

Step-by-step explanation:

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According to the graph, which range value corresponds to a domain value of 2?
Mekhanik [1.2K]

Answer:

D

Step-by-step explanation:

Simply put, domain means the x value and range means the y value.

<em><u>The question asks for the corresponding range (y-value) for domain (x-value) of 2. </u></em>

Looking at the graph, x value of 2 corresponds to y value of 4. So the answer is 4.

Correct answer is D

5 0
3 years ago
Read 2 more answers
What is the surface area 1ft 1ft 1ft?
Elodia [21]

Answer:

6 ft^2

Step-by-step explanation:

If the object in question is a cube, then we could say the length is 1, the depth is 1 and the height is 1, in which case each side of the cube has an area of 1 ft^2.  

There are 6 such sides, so the total surface area is 6 ft^2.

Next time please be explicit in naming the shape, either verbally or with a diagram.

4 0
3 years ago
PLEASE HELP ME WITH THIS!! ILL GIVE BRAINLIEST.
LekaFEV [45]

Answer:

See below.

Step-by-step explanation:

A correct.

B correct.

C correct.

D correct.

E incorrect.

F correct.

G incorrect.

H correct.

I incorrect.

J incorrect.

K correctt.

-hope it helps

4 0
2 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
2 years ago
Read 2 more answers
A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
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