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jolli1 [7]
3 years ago
9

A square has side length (7x-2) in. What is the area of the square?

Mathematics
1 answer:
Elza [17]3 years ago
4 0
Because the square has similar lengths, the equation would be
(7x-2)(7x-2)
We can use FOIL to solve this:
The area is 49x^2 - 28x + 4 in^2.
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Combine as indicated by the signs. 8-y/3y + y+2/9y - 2/6y
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Answer:

26 + y

----------

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Step-by-step explanation:

Your using parentheses here would remove a great deal of ambiguity.  Looking at your 8-y/3y + y+2/9y - 2/6y, I have interpreted it to mean:

(8-y)/3y + (y+2)/9y - (2/6)y.  For example, without parentheses, your 8-y/3y might be interpreted differently, as 8   -   y/(3y), or 8 - 1/3.

Looking at (8-y)/3y + (y+2)/9y - (2/6)y again, we see three different denominators:  3y, 9y and 6 y.  The LCD here is 9y.  Multiplying all three terms of  (8-y)/3y + (y+2)/9y - (2/6)y by the LCD, we get:

3(8-y) + (y+2) + 3y.  We must now divide this by the LCD:

3(8-y) + (y+2) + 3y

--------------------------

            9y

Next we need to perform the indicated multiplication:

24 - 3y + y + 2 + 3y

----------------------------

            9y

and then to combine like terms:

24 + 2 - 3y + y + 3y,           26 + y

----------------------------   or    -----------

              9y                             9y

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Step-by-step explanation:

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