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3 years ago

A square has side length (7x-2) in. What is the area of the square?

1 answer:

4 0

Because the square has similar lengths, the equation would be
(7x-2)(7x-2)
We can use FOIL to solve this:
The area is 49x^2 - 28x + 4 in^2.

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a trail is 5 miles long. carlos walks 2/3 of the trail and runs the rest. how many miles does carlos walk?

lana [24]

Answer:

as 1 mile = 1.609 km

so 5miles = 8.045 km

so 2/3 of the trail = 2/3 × 8.045 = 5.3633333 (ans)

Hope it helps

8 0

3 years ago

For every 5 hours he works Andrew gets paid $60.20. How much is Andrew paid per hour

Varvara68 [4.7K]

Andrew gets paid $12.05 cents per hour

6 0

3 years ago

Read 2 more answers

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

A man was 24 years old when his son was born . Now he is three times as old as his son . So how old is his son