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3 years ago

Which statement is not true about the data shown by the box plot below?

Mathematics

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

c. Three fourths of the data is greater than 65.

Step-by-step explanation:

A. is right, half of the data does lie between 53 and 74.
B. is right, when calculated, the range is 57.
C. is wrong.
D. is right, the median of the lower half of the data is 53.

I've attached a helpful image of box-and-whisker plots!

You might be interested in

Name the parts of the following expression: 2x+3-4x+7

lisov135 [29]

Answer:

Step-by-step explanation:

2x and -4x are like terms because they both have an x attached.3 and 7 are also like term.the number 2 is a coefficient because attached to x.-4 is also a coefficient

4 0

3 years ago

I need help with this, please answer right I will give brainelist

Gekata [30.6K]

Answer:

1 D. 400 spins

2 C.4/20

3 A. 6/20

Step-by-step explanation:

The more times you run a probability-based trial, the more likely you are to get close to the theoretical frequency.

Since 1 and 2 represent goals, just find the options that have three/four 2's and 1's. These are 5212, 2152, 2512, and 2112. Since there are 4 options out of 20, we can say our probability is 4/20

Since 1 and 2 represent goals, we have to find the options where there are no 1's or 2's. These are 6643, 3554, 4533, 6634, 4536, and 5546. Since there are 6 options out of 20, we can say our probability is 6/20

8 0

3 years ago

A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3

Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

And let the time the plane can fly 480 miles against the wind be t

(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

Flying against the wind

(Velocity of plane relative to the wind) = (480/t)

(Velocity of the plane) = v

(Velocity of the wind) = 30 mph

(480/t) = v - 30

t = 480/(v-30) (eqn 1)

Flying with the wind

(Velocity of plane relative to the wind) = 540/(t-1)

(Velocity of the plane) = v

(Velocity of the wind) = -30 mph

540/(t - 1) = v + 30

t - 1 = 540/(v+30) (eqn 2)

Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

Multiply through by (v+30)(v-30)

480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

v² + 60v - 31500 = 0

Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

3 0

2 years ago

Each interior angle of a regular hexagon is 4x+24°. What is x?

Oduvanchick [21]

Each interior angle of a regular hexagon is 120°.
.. 4x +24° = 120°
.. 4x = 96° . . . . . . . subtract 24°
.. x = 24° . . . . . . . . divide by 4

7 0

3 years ago

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is