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3 years ago

Which statement is not true about the data shown by the box plot below?

Mathematics

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

c. Three fourths of the data is greater than 65.

Step-by-step explanation:

A. is right, half of the data does lie between 53 and 74.
B. is right, when calculated, the range is 57.
C. is wrong.
D. is right, the median of the lower half of the data is 53.

I've attached a helpful image of box-and-whisker plots!

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Write 68,127,000,000,000,000 in scientific notation. (x10^

Alexeev081 [22]

Answer:

6.8127 × 10^16

Step-by-step explanation:

Hope this helps:)

7 0

3 years ago

Read 2 more answers

• A rational number is such that when you multiply it by

Tatiana [17]

Answer:

The number is -1/2.

Step-by-step explanation:

I am assuming they are fractions. So we have the equation:

5/2 x + 2/3 = -7/12

We multiply through by 12 to eliminate the fractions:

5/2 * 12 x + 2/3 * 12 = -7/12 * 12

30x + 8 = -7

30x = -15

x = -15/30

x = -1/2.

7 0

3 years ago

PLEASEE HELP AGAINNNN!!!!<br> If a1 = 4 and an = -4an - 1 then find the value of a6

sertanlavr [38]

The 6th term of the geometric sequence is of -4096.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term.

For this problem, we have that:

The first term is $a_1 = 4$ .

$a_n = -4a_{n - 1}$ , hence the common ratio is q = -4.

Thus the 6th term of the sequence is found as follows:

$a_6 = a_1q^5 = 4(-4)^5 = -4096$

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

6 0

1 year ago

The value of the solid's surface area is equal to the value of the solid's volume. Find the value of x

scoray [572]

Answer:

Step-by-step explanation:

6s^2=s^3

divide by s^2 on both sides to get 6=s. There is your answer

4 0

3 years ago

What equation best models this data?(use y to represent the population of rabbits and t to represent the year, assuming that 201

liraira [26]

If we see the data closely, a pattern emerges. The pattern is that the ratio of the population of every consecutive year to the present year is 1.6

Let us check it using a couple of examples.

The rabbit population in the year 2010 is 50. The population increases to 80 the next year (2011). Now, $\frac{80}{50}=1.6$

Likewise, the rabbit population in the year 2011 is 80. The population increases to 128 the next year (2012). Again, $\frac{128}{80}$ $=1.6$

We can verify the same ratio with all the data provided.

Thus, we know that the population in any given year is 1.6 times the population of the previous year. This is a classic case of a compounding problem. We know that the formula for compounding is as:

$F=P\times r^n$

Where $F$ is the future value of the rabbit population in any given year

$P$ is the rabbit population in the year "0" (that is the starting year 2010) and that is 50 in this question. (please note that there is just one starting year).

$r$ is the ratio multiple with which the rabbit population increases each consecutive year.

$n$ is the nth year from the start.

Let us take an example for the better understanding of the working of this formula.

Let us take the year 2014. This is the 4th year

So, the rabbit population in 2014 should be:

$F_{2014} =50\times(1.6)^4\approx328$

This is exactly what we get from the table too.

Thus, $F=P\times r^n$ aptly represents the formula that dictates the rabbit population in the present question.

4 0

3 years ago