I need help with the answers

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

Answer:

i dont get it

Step-by-step explanation:

You might be interested in

16 homework papers to grade and 14 exit tickets what's the ratio

schepotkina [342]

The ratio would be 16:14 and then simplify it to 8:7

3 0

3 years ago

How many ways are there to choose a committee of 7 people from a group of 10 people?

Aneli [31]

I think it's 720
Have a GREAT day!

7 0

3 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Dahasolnce [82]

Factor by using the rational roots test, and find that -2 is a root.

Replace X with -2 and simplify each term.

Divide the polynomial by (x+2)

The final answer becomes x = -2 and x = -1/2 +/-√3/2i

The first choice is the correct one.

5 0

3 years ago

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

This means the area is given by the integral,

$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.