Answer:
the answer is 40 because you count all the squares that are in the shape
Step-by-step explanation:
Let's solve your equation step-by-step.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−<span>30
</span></span></span>Step 1: Simplify both sides of the equation.<span><span>−<span>5<span>(<span>x−4</span>)</span></span></span>=<span>−30</span></span>
<span>Simplify: (Show steps)</span><span><span><span>−<span>5x</span></span>+20</span>=<span>−<span>30
</span></span></span>Step 2: Subtract 20 from both sides.<span><span><span><span>−<span>5x</span></span>+20</span>−20</span>=<span><span>−30</span>−20</span></span><span><span>−<span>5x</span></span>=<span>−<span>50
</span></span></span>Step 3: Divide both sides by -5.<span><span><span>−<span>5x</span></span><span>−5</span></span>=<span><span>−50</span><span>−5</span></span></span><span>x=<span>10
</span></span>Answer:<span>x=<span>10</span></span>
<u><em>PART A</em></u>
If 4 pounds = 10 dollars...
4/2 = 2
10/2 = 5
<u>So for 2 pounds, it would cost </u><u>$5.00</u>
Now for the 1 pound one
4/1 = 4
10/4 = 2.5
<u>For the 1 pound one, it would cost </u><u>$2.50</u>
<u></u>
<u><em>PART B</em></u>
We know that 4 pounds = 10 bucks
Since 1 is 1/10 of 10 (in the cost section), we have to apply this to the pounds section. 4/10 = 0.4. Therefore, <u>$1 = 0.4lb</u>
Now for the last blank...
Since $1 = 0.4, we multiply that by 9. 0.4 x <u>$9 = 3.6lb</u>
<u></u>
<em>HOPE THIS HELPED</em>
Answer:
5 games
Step-by-step explanation:
To find how many games the team scored at least 70 points, we need to look at the 7 on the stem side. The 7 means 70, and we add the digits on the leaf side. For example, 7 | 2 is 72. The numbers on the leaf side are: 1, 1, 2, and 3.
There are no points for the 8 on the stem side, but on 90, there is one digit on the leaf side: 1. So, the points they scored over 70 are 71, 71, 72, 73, and 91, which equals to five games.
A set of ordered pairs is called a relation. The set of all first components of the ordered pairs of a relation is the domain of the relation, and the set of all second components of the ordered pairs is the range of the relation. :)
