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ivolga24 [154]
2 years ago
11

Idk. just say random multiples of 24.

Mathematics
2 answers:
serg [7]2 years ago
8 0

Answer:

48,72,96,120,144,168,192,216,240,264,288,312,336,360,384,408,432,456

Step-by-step explanation:

vova2212 [387]2 years ago
6 0

Answer:

Which unit rate is equivalent to 14 miles per gallon? (1 point

Step-by-step explanation:

i am so glad to hear you are Incredible in messages and please contact us at the free points and see what hi rjha is the most important to you to you amanpreet your support for your support for your child to be a child of your

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Is y-x=2x-2/3y a linear equation
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Answer:

Step-by-step explanation:

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3 years ago
What is give an example of a unit rate used in a real world situation? Plz I'm literally so confused lol.
nignag [31]

Answer:

Miles per hour. (mph)

Step-by-step explanation:

This can be used in almost everyday, since most people today drive around in cars, and use mph to see how fast they are going per hour.

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8 0
3 years ago
Read 2 more answers
Which of the following statements is not always true? A. In a rhombus, both pairs of opposite sides are parallel. B. In a rhombu
Sunny_sXe [5.5K]
The correct answer is C. I just took a test and answered B but that is not the correct answer. it is actually C
8 0
2 years ago
A population of a particular yeast cell develops with a constant relative growth rate of 0.4225 per hour. The initial population
Ksju [112]

Answer: The population after 3 hours is 13.9 mill.

Step-by-step explanation:

When we have an exponential with:

A  = initial population.

r = constant relative growth rate:

t = time.

The function that models this is:

P(t) = A*e^(k*t)

In this case we know that:

A = 3.9 mill.

r = 0.4225 1.

Then the function that models the population of this yeast cell is:

P(t) = (3.9 mill)*e^(0.4225*t)

where t represents the time in hours.

Then if we want to know the population after 3 hours, we should replace t by 3.

P(3) = (3.9 mill)*e^(0.4225*3) = 13.85 mill.

And we want to round our answer to one decimal place, then we must look at the second decimal place, we can see that is a 5, so we should round up.

The population after 3 hours is 13.9 mill.

8 0
3 years ago
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
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