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puteri [66]
2 years ago
7

Help please it’s annoying

Mathematics
1 answer:
kap26 [50]2 years ago
8 0
I can’t see the picture
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In Fig. 6.28, find the value of x and y and then show that AB || CD.​
poizon [28]

Answer:

Maybe 180° -50° = 130°

So I think x= 130°

Step-by-step explanation:

My opinion though

6 0
3 years ago
What x-values are a solution to the system? Select each correct answer the answers are
Brut [27]
I think the sabers are X=2 and X=-2
6 0
3 years ago
PLEASE HELP IM TIMED!! WILL GIVE BRAINLEST!!
Goshia [24]

Answer:

The answer is C

Step-by-step explanation:

An isosceles triangle has two angles that measure the same, so...

30 + 30 = 60

180 - 60 = 120

No

____________

45 + 45 = 90

180 - 90 = 90

No

____________

60 + 60 = 120

180 - 120 = 60

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5 0
3 years ago
A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0
3 years ago
Mick dropped 2 pennies and he had 7 how many does he have left
sesenic [268]

Answer:

5

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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