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arlik [135]
3 years ago
11

4.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

$320,000

Step-by-step explanation:

70%/100%=224,000/X

(224,000*100)/70=320,000

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Explain how the graph of a quadratic function relates to the solutions of the related quadratic equation.
OleMash [197]

Answer:

The zeros of a quadratic function are the solutions of the related quadratic equation. If the graph of a quadratic function crosses the x-axis, there will be two real number solutions. If the graph of a quadratic function just touches the x-axis, there will be one unique real number, or double root, solution. If the graph of a quadratic function does not cross the x-axis, there will be no real number solution.

Step-by-step explanation:

Did the question.

8 0
3 years ago
What is the sum of the measures of the interior angles of a 14-gon?
ICE Princess25 [194]
D 2520 -------------------------------------------
6 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION
alekssr [168]

Answer:

The second option, 1,008 cm²

Step-by-step explanation:

   This shape has 5 sides to solve for with reguards to surface area.

   Let us solve for them all.

[1 & 2 - the triangles]

12 * 9 = 108 cm²

-> I am not going to divide since we have 2 congruent triangles

[3 - the bottom side]

25 * 12 = 300 cm²

[4 - the side facing away]

25 * 9 = 225 cm²

[5 - the side facing up]

25 * 15 = 375 cm²

   Now we will add them together for the total.

108 + 300 + 225 + 375 = 1,008 cm²

             The surface area for the triangular prism shown is 1,008 cm².

7 0
2 years ago
Read 2 more answers
The quantity y varies directly as x and inversely as z. When x is 10 and z is 4, y is 15. What is y when x is 20 and z is 6?
frosja888 [35]
Y=(kx)/z


15=(k10)/4
15=(5k/2)
15=k(5/2)
ties both sides by 2/5 to clear fraction
6=k

y=(6x)/z

x=20
z=6
y=(6*20)/6
y=20
8 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Katyanochek1 [597]

Answer:

<h2>x = 1, y = 3 → (1, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3

5 0
3 years ago
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