Orbital shell notation of fluorine is 2. 7 while that of oxygen s 2. 6. This means that these elements (that follow each other in the periodic table) will have high electronegativity in molecules due to their high atomic number (which causes them to strongly attract electron orbital shell closer to their nucleus). NB: Atomic number of a peroid increased from left to right of the periodic table.
Therefore, in the first molecule, the negative dipole would most likely be located between the F atoms In the second molecule the negative molecule would be most likely located in the between the O and F atoms.
Answer:
A. True
Explanation:
The octane number is determined by comparing the characteristics of gasoline to isooctane (2,2,4-trimethylpentane) and heptane. The correct option is option A.
Basically, the higher the octane number, the greater the resistance of the gasoline to knocking.
Answer:
amount of silver chloride required is 0.015 moles or 2.1504 g
Explanation:
0.1M AgCL means 0.1mol/dm³ or 0.1mol/L
1L = 1000mL
if 0.1mol of AgCl is contained in 1000mL of solution
then x will be contained in 150mL of solution
cross multiply to find x
x = (0.1*150)/1000
x= 0.015 moles
moles of silver chloride present in 150 mL of solution is 0.15 moles
To convert this to grams, simply multiply this value by the molar mass of silver chloride
molar mass of silver chloride AgCl =107.86 + 35.5
=143.36 g/mol
mass of AgCl = moles *molar mass
=0.015*143.36
=2.1504g
=
Answer:
The answer is D) all of the above
Explanation:
This is because if something has mass then it is composed of matter.
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Answer:
w = 164.62 g
Explanation:
molarity of a solution is given as -
Molarity (M) = ( w / m ) / V ( in L)
where ,
m = molecular mass ,
w = given mass ,
V = volume of solution ,
From the question ,
M = 500 mM = 0.5 M
( since , 1 mM = 1 / 100 M)
As we know , the molecular mass of potassium ferricyanide = 329.24 g/ mol
V = vol.of solution = 1 L
w = ?
<u>To find the value of w , using the above formula , and putting the respected values , </u>
Molarity (M) = ( w / m ) / V ( in L)
0.5 = ( w / 329.24 ) / 1 L
w = 164.62 g
