Answer:
0,051g of O₂ are consumed
Explanation:
The reaction of precipitation of Fe(II) is:
4Fe(OH)⁺(aq) + 4OH⁻(aq) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s)
The moles of Fe(II) you have in 85ml of 0.075 M Fe(II) are:
0,085L×0,075M = 6,4x10⁻³ moles of Fe(II)
For the reaction, you require 4 moles of Fe(II) and 1 mol of O₂(g) to precipitate the iron. Thus, moles of O₂(g) you require are:
6,4x10⁻³ moles of Fe(II)×
= 1,6x10⁻³ moles of O₂(g)
These moles are:
1,6x10⁻³ moles of O₂(g)×
= <em>0,051g of O₂ are consumed</em>
<em></em>
I hope it helps!
<span>metallic elements are malleable because of its ability for the atoms to roll on top of one another without breaking its metallic bond (This is because it is attracted with more force, and is the reason why they have higher melting/boiling points); however, a nonmetals form molecular bonds which doesn't have this property</span>
×
sodium ions in 2.11 mol of sodium carbonate.
<h3>
What is sodium carbonate?</h3>
The sodium carbonate, the inorganic substance with the
formula, is also known as washing soda, soda ash, and soda crystals.
All of the forms are water-soluble, odourless, white salts that produce slightly alkaline solutions in water. In the past, it was recovered from the ashes of plants that were raised in soils high in salt.
The term "soda ash" originated to refer to sodium carbonate because the ashes of these sodium-rich plants were probably distinct from the wood ashes that were originally used to make potash. The Solvay technique is used to produce it in large amounts from limestone and sodium chloride.
Learn more about sodium carbonate ![Na_2CO_3](https://tex.z-dn.net/?f=Na_2CO_3)
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The answer is: Test
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