A Cell with few energy needs would most likely contain a small number of Mitochondria.
- All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
- They transform glucose into ATP, a chemical with a huge energy storage capacity.
- Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
- Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
- Vacuoles are typically tiny and aid in the sequestration of waste.
- The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.
Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.
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The mixture contains 62 % one isomer and 38 % the enantiomer.
Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.
Then % (<em>S</em>) = 100 % -62 % = 38 %
ee = % (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %
The finagling in the hole
Potassium hydroxide is a strong base and hydrobromic acid is a strong acid. This implies that the pH of the end-point [neutralization] of their titration will be around pH 7. A good indicator for this kind of pH is bromthymol blue. This is because this indicator changes its colour at pH 7.
The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles
<h3>Balanced equation </h3>
2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
<h3>How to determine the theoretical yield of NaBr</h3>
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
Therefore,
2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr
Therefore,
Thus, the theoretical yield of NaBr is 7.08 moles
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