Answer:
boiling point and melting point.
Mass of ammonia produced : 121.38 g
<h3>Further explanation</h3>
Given
Reaction
3H₂(g) + N₂(g) ⇒ 2NH₃(g)
100g of N₂
Required
Ammonia produced
Solution
mol of N₂ :

From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :

mass of NH₃(MW=17 g/mol) :

Answer:
Empirical formula is PNCl₂
Explanation:
Percent composition means that 100 g of compound has x g of each element.
In 100 g of compound x, we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl.
So, let's make some rules of three:
In 100 g of compound we have 26.73 g of P, 12.09 g of N, 61.18 g of Cl
In 579.43 g of compound we have:
(579.43 . 26.73) / 100 = 155 g of P
(579.43 . 12.09) / 100 = 70 g of N
(579.43 . 61.18) / 100 = 354 g of Cl
Let's convert the mass of the elements in moles.
155 g of P / 30.97 g/mol = 5 P
70 g / 14 g/mol = 5 N
354 g / 35.45 g/mol = 10 Cl
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