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Vladimir79 [104]
3 years ago
12

Kyoko is a hard-working college senior. One Saturday, she decides to work nonstop until she has answered 150 practice problems f

or her math course. She starts work at 8:00 AM and uses a table to keep track of her progress throughout the day. She notices that as she gets tired, it takes her longer to solve each problem.
Time
Total Problems Answered
8:00 AM 0
9:00 AM 60
10:00 AM 105
11:00 AM 135
Noon 150
Use the table to answer the following questions.
The marginal, or additional, benefit from Kyoko’s second hour of work, from 9:00 AM to 10:00 AM, is
45
problems.
The marginal benefit from Kyoko’s fourth hour of work, from 11:00 AM to noon, is
15
problems.
Later, the teaching assistant in Kyoko’s math course gives her some advice. “Based on past experience,” the teaching assistant says, “working on 52.5 problems raises a student’s exam score by about the same amount as reading the textbook for 1 hour.” For simplicity, assume students always cover the same number of pages during each hour they spend reading.
Given this information, in order to use her 4 hours of study time to get the best exam score possible, how many hours should she have spent working on problems, and how many should she have spent reading?

1 hour working on problems, 3 hours reading
2 hours working on problems, 2 hours reading
3 hours working on problems, 1 hour reading
4 hours working on problems, 0 hours reading
Business
1 answer:
sasho [114]3 years ago
6 0

Answer:

c

Explanation:

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Answer:

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Explanation:

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3 years ago
Let $S$ be the set of complex numbers of the form $a + bi,$ where $a$ and $b$ are integers. We say that $z \in S$ is a unit if t
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Answer:

Number of units possible in S are 4.

Explanation:

Given <em>S</em> is a set of complex number of the form a+bi where <em>a</em> and <em>b</em> are integers.

z\in S is a unit if w\in z exists such that zw=1.

To find:

Number of units possible = ?

Solution:

Given that:

zw = 1

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|zw| = |1|

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|z_1z_2|=|z_1|.|z_2|

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|zw| = |1|\\\Rightarrow |zw| =|z|.|w| =1\\\Rightarrow |z|=\dfrac{1}{|w|}......... (1)

Let z=a+bi

Then modulus of z is   |z| = \sqrt{a^2+b^2}

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(a = 1, b = 0) ,  (a = -1, b = 0), (a = 0, b = 1) OR (a = 0, b = -1)

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1.\ 1 + 0i = 1\\2.\ -1 + 0i = -1\\3.\ 0+ 1i = i\\4.\ 0 -1i = -i

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