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Natalka [10]
3 years ago
10

Olivia wrapped a string around a circle and found it was 30 mm long. Approximately, what is the radius of this circle

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:7.5

Step-by-step explanation: cause I looked it up lol

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On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
Mrrafil [7]
<h3>Answer:  Choice C.   (1,0)</h3>

============================================================

Explanation:

Point H is at (-2,2) and J is at (4,-2)

Focusing on the x coordinates, the midpoint is (x1+x2)/2 = (-2+4)/2 = 1.

The y coordinates have a midpoint of (y1+y2)/2 = (2+(-2))/2 = 0.

The midpoint is at (1,0). That's why the answer is choice C.

--------------------------

This next section is optional.

Points I and K are located at (4,3) and (-2,-3) respectively

Averaging the x coordinates gets us (x1+x2)/2 = (4+(-2))/2 = 1

Doing the same for the y coordinates gets us (y1+y2)/2 = (3+(-3))/2 = 0

We end up with the same midpoint (1,0)

The midpoint being the same for both diagonals proves that each diagonal is bisected, ie cut in half.

3 0
3 years ago
i forgot how to find equivalent fractions. i know that the bottom would be times by 3 to get 18 but if you times 3 by 3 it would
tester [92]
Set up a proportion.  take 3/6 = 20/x
Cross multiply 3 * x = 6 * 20
Simplify  3x = 120
Divide by 3  x = 40
So the denominator of the bottom fraction is 40
6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!
murzikaleks [220]

Answer:

Hi,

Step-by-step explanation:

x>=0

y>=0

x+y-5<=0 line passing through (0,5)  and (5,0) with (0,0) in minus region

2x-y-8<=0 line passing trough (0,-8) and (4,0) with (0,0) in minus region

Answer C

6 0
2 years ago
What is the square root of 24.
Tpy6a [65]

Answer:4.898979486

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)
Anna71 [15]
GIVEN:

5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)

remember:

\sqrt{u} = {u}^{ \frac{1}{2} }

And

{u}^{n} \times {u}^{m} = {u}^{n + m}

SOLVE:

start by multiplying the factors:

5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))

simplify by combing like terms. Most terms subtract off, leaving:

5( {u}^{6} - 1)

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

5( {u}^{3} - 1)( {u}^{3} + 1)

I'm not exactly sure what form they want the answer in...

so taking the square root:

\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }

so my best answer is:

{5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }
or the more factored form:

{5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!
7 0
3 years ago
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