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GaryK [48]
3 years ago
7

Which recursive function represents this sequence? -8, -12, -16, -20, -24 …

Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:

<h2>brainiest me</h2>

Step-by-step explanation:

mathematics, 18.07.2020 01:01 8.07.2020 01:01

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21=6r - 3 <br><br> R=? <br><br> What is R?
sleet_krkn [62]

Answer:4

Step-by-step explanation:6 times 4 is 24 minus 3 is 21

8 0
4 years ago
Hello mee need help I’m going to get a whooping because I’m failing.
natulia [17]

Answer:

number 1,2,4

Step-by-step explanation:

these are all equal sides

8 0
3 years ago
Read 2 more answers
Approximate the value of 11−−√ to the nearest tenths place. Plot the approximation on the number line.
posledela

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

<em>Approximate the value of </em>\sqrt{11}<em> to the nearest tenths place. Plot the approximation on the number line.</em>

(Please have a look at the attached photo)

My answer:

The value nearest tenths place of \sqrt{11} is: 3.3

Hope it will find you well.

5 0
3 years ago
The gas gauge in a car shows it has 40% of a tank of gas. If the car has about 5 gallons, approximately how many gallons can the
-BARSIC- [3]
If 40% of a gas tank is equal to 5 gallons then:

0.40x=5

x=5/0.40

x=12.5

And so the tank can hold up to 12.5 gallons.
8 0
3 years ago
Consider the case0502 data from Sleuth3. &lt;&lt;&lt; This is the data. Sleuth3 is preloaded into R studio.
Finger [1]

Answer:

Consider the following calculations

Step-by-step explanation:

The complete R snippet is as follows

install.packages("Sleuth3")

library("Sleuth3")

attach(case0502)

data(case0502)

## plot

# plots

boxplot(Percent~ Judge, data=case0502,ylab="Values",

main="Boxplots of the Data",col=c(2:7,8),horizontal=TRUE)

# perform anova analysis

a<- aov(lm(Percent~ Judge,data=case0502))

#summarise the results

summary(a)

### we can use the independent sample t test here

sp<-case0502[which(case0502$Judge=="Spock's"),]

nsp<-case0502[which(case0502$Judge!="Spock's"),]

## perform the test    

t.test(sp$Percent,nsp$Percent)

The results are CHECK THE IMAGE ATTACHED

b)

> summary(a)

Df Sum Sq Mean Sq F value Pr(>F)

Judge 6 1927 321.2 6.718 6.1e-05 *** as the p value is less than 0.05 , hence there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge

Residuals 39 1864 47.8

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

c)

t.test(sp$Percent,nsp$Percent)

  Welch Two Sample t-test

data: sp$Percent and nsp$Percent

t = -7.1597, df = 17.608, p-value = 1.303e-06 ## as the p value is less than 0.05 , hence we reject the null hypothesis in favor of alternate hypothesis and conclude that there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined

alternative hypothesis: true difference in means is not equal to 0

95 percent confidence interval:

-19.23999 -10.49935

sample estimates:

mean of x mean of y

14.62222 29.49189

6 0
3 years ago
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