Answer:
straight line through (0,4) and (2,0), shade everything above it
Step-by-step explanation:
First solve the equality, which will give you a straight line.
Then check if the inequality (the > sign) means you have to shade the area above or below it.
2x + y = 4 can easily be solved by first taking x=0, then you find y=4, hence (0,4) is a solution.
Then take y=0, then you find 2x = 4 so x=2, hence (2,0) is a solution.
Plot these two points and draw a line through them.
Now, since 2x+y has to be larger than 4, all the points to the right and above the line are valid. So that's the area you have to shade.
Simplifying
5x(4y + 3x) = 5x(3x + 4y)
Reorder the terms:
5x(3x + 4y) = 5x(3x + 4y)
(3x * 5x + 4y * 5x) = 5x(3x + 4y)
Reorder the terms:
(20xy + 15x2) = 5x(3x + 4y)
(20xy + 15x2) = 5x(3x + 4y)
20xy + 15x2 = (3x * 5x + 4y * 5x)
Reorder the terms:
20xy + 15x2 = (20xy + 15x2)
20xy + 15x2 = (20xy + 15x2)
Add '-20xy' to each side of the equation.
20xy + -20xy + 15x2 = 20xy + -20xy + 15x2
Combine like terms: 20xy + -20xy = 0
0 + 15x2 = 20xy + -20xy + 15x2
15x2 = 20xy + -20xy + 15x2
Combine like terms: 20xy + -20xy = 0
15x2 = 0 + 15x2
15x2 = 15x2
Add '-15x2' to each side of the equation.
15x2 + -15x2 = 15x2 + -15x2
Combine like terms: 15x2 + -15x2 = 0
0 = 15x2 + -15x2
Combine like terms: 15x2 + -15x2 = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
Perform indicated multiplications on left side.
8-40x=13 subtract 8 from both sides
-40x=5 divide both sides by -40
x=-5/40
x=-1/8
Note: There are no mixed numbers in this problem.
