All categories

3 years ago

What is the probability of getting an odd number and a 4 sided shape on the spinner?

Mathematics

2 answers:

-Dominant- [34]3 years ago

4 0

Answer:

Step-by-step explanation:

3 odd numbers x 2 4-sided shapes = 6

tiny-mole [99]3 years ago

3 0

6! is your answer have a great day!

You might be interested in

An English professor assigns letter grades on a test according to the following scheme. A: Top 15% of scores B: Scores below the

lisabon 2012 [21]

Answer:

59 to 66

Step-by-step explanation:

Mean test scores = u = 74.2

Standard Deviation = $\sigma$ = 9.6

According to the given data, following is the range of grades:

Grade A: 85% to 100%

Grade B: 55% to 85%

Grade C: 19% to 55%

Grade D: 6% to 19%

Grade F: 0% to 6%

So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.

6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)

The formula for z score is:

$z=\frac{x-u}{\sigma}$

For z = -1.56, we get:

$-1.56=\frac{x-74.2}{9.6}\\\\ x = 59$

For z = -0.88, we get:

$-0.88=\frac{x-74.2}{9.6}\\\\ x = 66$

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)

7 0

4 years ago

295.6 divided by 10 with the power of 2

stealth61 [152]

Answer:

2.956

Step-by-step explanation:

$\frac{295.6}{10^2}$

= $\frac{295.6}{100}$

= 2.956

6 0

3 years ago

Read 2 more answers

What is the radical form of each of the given expressions?

earnstyle [38]

Answer:

$6^{\frac{1}{5} }=\sqrt[5]{6}$

$6^{\frac{7}{5} }=\sqrt[5]{6^7}$

$6^{\frac{1}{6} }=\sqrt[6]{6}$

$7^{\frac{1}{2} }=\sqrt[2]{7}$

$7^{\frac{5}{2} }=\sqrt[2]{7^5}$

$6^{\frac{9}{2} }=\sqrt[2]{6^9}$

Step-by-step explanation:

A radical is the root operation for n roots such as square root or cuberoot in the form $\sqrt[n]{x}$ . A fraction exponent $x^{m/n}$ can be converted to the radical form.