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2 years ago

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Mathematics

2 answers:

denpristay [2]2 years ago

7 0

For simple interest, the amount of interest (I) is calculated from the principal (P), the annual rate (r) and the number of years (t) using the formula

... I = P·r·t

Fill in the given numbers, and solve for t.

... 84 = 600·0.07·t . . . of course, you know that 7% = 7/100 = 0.07

... 84 = 42t . . . . . . . . simplify

... 84/42 = t = 2 . . . . divide by the coefficient of t

The time period is 2 years.

oksian1 [2.3K]2 years ago

6 0

Total = Principal × ( 1 + Rate ) ^ years

(Solved by taking logarithms)

Years = log (total / principal) / (log (1 + rate))

Years = log (684 / 600) / (log 1.07)

Years = log (1.14) / (log (1.07)

Years = 0.0569048513364726 / 0.0293837776852097

Years = 1.9366077414

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Answer:

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2 years ago

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Answer:

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2 years ago

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kumpel [21]

Answer:

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Step-by-step explanation:

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6 0

2 years ago

Make a the subject of a2+b2=c2

wel

Answer:

$a=\sqrt{c^2-b^2$

⇒ $a=\sqrt{(c+b)(c-b)}$ [Factorized form]

Step-by-step explanation:

Given expression:

$a^2+b^2=c^2$

We need to make $a$ the subject.

In order to do that we need to solve the expression for $a$ in terms of $b$ and $c$

We have,

$a^2+b^2=c^2$

Subtracting both sides by $b^2$

$a^2+b^2-b^2=c^2-b^2$

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Taking square root both sides in order to remove square of $a$

$\sqrt{a^2}=\sqrt{c^2-b^2}$

$a=\sqrt{c^2-b^2$

The difference of squares can be factorized and written as:

$a=\sqrt{(c+b)(c-b)}$ [difference of squares $x^2-y^2=(x+y)(x-y)$ ]

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2 years ago