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pochemuha
3 years ago
13

Will someone plz work this out for me

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0
The answer equals 2a+87.
klio [65]3 years ago
5 0
3(4a+9)-10(a-6)
(distribute)
12a+27-10a+60
(add common terms)
2a+87
(have x be alone on one side of the equation, in this case by subtracting 87 from both sides)
2a=-87
(divide both sides by 2)
a=43.5
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Question 5 (Solving Problema) lon 5 Solving Problems] Write 24 18 in slmplest form​
otez555 [7]

Answer:

4/3

Step-by-step explanation:

reduce the fraction by a factor of 6

pretty sure you mean write 24/18 in simplest form so that's the answer

Hope this helps! :)

8 0
2 years ago
Multiply 2 2/3 and 1 5/6 Simplify the answer and write as a mixed number.
fiasKO [112]

The answer as a mixed number is 4 8/9

The first step is to write out the fractions and multiply both fractions

2 2/3 × 1 5/6

= 8/3 × 11/6

= 44/9

Convert to a mixed number

= 4 8/9 (as a mixed number)

Hence the mixed number gotten from the simplification is 4 8/9

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1 year ago
Change 5.5 into centimetres
jolli1 [7]
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8 0
3 years ago
Jim ran 200 meters in 30.4 seconds. Mac ran 100 meters in 30.4 seconds. Who ran faster?
Andrews [41]

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8 0
3 years ago
Read 2 more answers
Find the local max and min values of f(x)=x^2/x-1 using both first and second derivative tests
uranmaximum [27]
Hmm, the 2nd derivitve is good for finding concavity

let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient

so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x

so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points

f'(-1)>0
f'(1.5)<0
f'(3)>0

so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)


we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense




local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
6 0
3 years ago
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